Report a QuestionPlease email hello@efficientengineer.com. Question 9 Material Properties | Stress-strain curves | difficulty level 1The graph below shows the stress-strain curve obtained from a tensile test performed for an unknown material. Determine the Young’s modulus of the material in GPa, to the nearest 1 GPa. Check Report this questionExplanationYoung's modulus is the slope of the stress-strain curve in the elastic region. It can be determined from Hooke's law:$$\sigma = \varepsilon E$$From the graph below we have $\sigma = 80 \mathrm{MPa}$ for a strain of 2%, which gives:$$E = \frac{80 \mathrm{MPa}}{0.02} = 4 \mathrm{GPa}$$Your Results Restart with New Questions Change Quiz Settings Review the Questions
