Report a QuestionPlease enable JavaScript in your browser to complete this form.Question IDReason for reporting this questionToo easy / too difficultTypo in questionAnswer is incorrectOtherDescription *Submit Question 77 Statics | Mechanical advantage | difficulty level 1A gear train is arranged as a speed multiplier with Gear A driving Gear B. Gear A has 12 teeth and rotates at a speed of 1800 RPM (revolutions per minute). Gear B has 36 teeth. What is the rotational speed of Gear B? 600 RPM 5400 RPM 1800 RPM 3600 RPM Report this questionExplanationBecause Gear B has more teeth than Gear A, one full rotation of Gear A will correspond to less than one full rotation of Gear B. This means Gear B must be rotating at a lower speed than Gear A.The speed of gears in a gear train is inversely proportional to the number of teeth they have, based on the gear ratio. The gear ratio can be determined using the formula: $$\mathrm{Gear Ratio} = \frac{\mathrm{Teeth_{Gear A}}}{\mathrm{Teeth_{Gear B}}} = \frac{12}{36} = \frac{1}{3}$$ If Gear A rotates at 1800 RPM, Gear B will rotate at: $$\frac{1800\mathrm{RPM}}{3} = 600 \mathrm{RPM}$$Your Results Restart with New Questions Change Quiz Settings Review the Questions
