Report a QuestionPlease enable JavaScript in your browser to complete this form.Question IDReason for reporting this questionToo easy / too difficultTypo in questionAnswer is incorrectOtherDescription *Submit Question 62 Mechanics of Materials | Torsion | difficulty level 2A circular bar is loaded in pure torsion as shown below. This generates a maximum shear stress on the surface of the bar that is equal to 100 MPa. What is the minimum principal stress on the surface of the bar? -100 MPa 0 MPa -25 MPa -50 MPa Report this questionExplanationThis problem is easiest to solve using Mohr's circle.Torsional loading for a circular bar generates a plane stress, pure shear state of stress on the surface of the bar. For pure shear the normal stress will be zero for the orientation of the stress element at which the maximum shear stress occurs. The maximum shear stress is equal to 100 MPa, which defines the radius of the circle.This allows us to draw Mohr's circle for this stress state, which is shown below.The minimum principal stress $\sigma_2$ is therefore equal to -100 MPa.Your Results Restart with New Questions Change Quiz Settings Review the Questions
